2/3^z=20

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Solution for 2/3^z=20 equation: 



2/3^z=20

We move all terms to the left:

2/3^z-(20)=0



Domain of the equation: 3^z!=0

z!=0/1

z!=0

z∈R



We multiply all the terms by the denominator


-20*3^z+2=0

Wy multiply elements

-60z+2=0

We move all terms containing z to the left, all other terms to the right

-60z=-2

z=-2/-60

z=1/30

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